Serbian Championship 2023


Date
Apr 1 - 2, 2023
City
Belgrade, Serbia
Venue

Mathematical Grammar School

Address
Kraljice Natalije 37, Beograd 11000, Srbija
Details

Pratite znakove da dođete do hale (2. sprat). / Follow the signs to get to the venue (2nd floor).

Contact
Organization team
Organizers
Aleksa Radovanović, Luka Jankovic, Luka Stošić, and Đorđe Timotijević
WCA Delegate
Aleksa Radovanović
Download all the competition's details as PDF here.
Information

(SRB)

Serbian Championship 2023 je četrnaesto po redu takmičenje koje se održava u Srbiji. Svako može da se takmiči, nezavisno od njihove nacionalnosti ili godina, ali moraju biti upoznati sa WCA Regulacijama i moraju da ih pročitaju pre takmičenja.


(ENG)

Serbian Championship 2023 is the 14th speedcubing competition in a row that's being held in Serbia. Anyone can participate, no matter which nationality or age they are, but they need to be familiar with the WCA Regulations and read them before the competition.

Events
Main event
Competitors
63
Registration period

Online registration opened Monday, March 6, 2023 at 7:00 PM UTC and closed Sunday, March 12, 2023 at 9:18 AM UTC.

Registration requirements
This competition is over, click here to display the registration requirements it used.
Highlights
Click here to display the highlights of the competition.

Benedek Zimányi won with an average of 8.39 seconds in the 3x3x3 Cube event. Bálint Csengő finished second (8.42) and Firmin Brault finished third (8.59).

3x3x3 Cube

# Name Best Average Representing Solves
1 Benedek Zimányi 6.72 8.39 Hungary 9.337.927.9313.136.72
2 Bálint Csengő 8.03 8.42 Hungary 8.038.598.628.0610.27
3 Firmin Brault 8.22 8.59 France 8.428.709.138.228.65

2x2x2 Cube

# Name Best Average Representing Solves
1 Marcel Ručigaj 1.44 2.15 Slovenia 1.442.482.792.171.79
2 Bálint Csengő 2.10 2.67 Hungary 2.102.852.842.332.98
3 Szabolcs Szántai 2.16 2.75 Hungary 2.163.082.882.303.41

4x4x4 Cube

# Name Best Average Representing Solves
1 Bálint Csengő 30.14 31.11 Hungary 31.0535.0930.1530.1432.14
2 Firmin Brault 28.98 32.31 France 36.3432.1130.8228.9834.00
3 Szabolcs Szántai 32.44 35.95 Hungary 32.4435.4432.5639.8440.89

5x5x5 Cube

# Name Best Average Representing Solves
1 Bence Barát 55.84 1:03.15 Hungary 1:02.5657.5755.841:09.331:12.46
2 Bálint Csengő 53.52 1:03.47 Hungary 1:06.641:03.9153.521:00.621:05.88
3 Firmin Brault 1:03.69 1:07.67 France DNF1:08.381:03.691:04.021:10.62

6x6x6 Cube

# Name Best Average Representing Solves
1 Bence Barát 1:43.33 1:51.18 Hungary 1:43.332:04.291:45.93
2 Bálint Csengő 1:54.63 1:56.24 Hungary 1:57.471:56.611:54.63
3 Vincenzo Maria Gammino 2:05.27 2:07.86 Italy 2:07.962:10.342:05.27

7x7x7 Cube

# Name Best Average Representing Solves
1 Bence Barát 2:43.10 2:52.93 Hungary 2:54.732:43.103:00.95
2 Vincenzo Maria Gammino 2:41.78 2:53.70 Italy 3:08.892:41.782:50.42
3 Bálint Csengő 2:47.76 3:01.38 Hungary 3:20.722:55.652:47.76

3x3x3 Blindfolded

# Name Best Average Representing Solves
1 Jakov Srečković 26.15 NR DNF Croatia 26.1527.49DNF
2 Bálint Csengő 30.60 DNF Hungary 40.1530.60DNF
3 Marcel Ručigaj 42.42 NR DNF Slovenia 42.42DNFDNF

3x3x3 One-Handed

# Name Best Average Representing Solves
1 Matej Marčok 12.03 13.13 NR Serbia 13.1212.0312.3314.5313.95
2 Bálint Csengő 12.34 13.75 Hungary 13.3717.7512.5015.3812.34
3 Szabolcs Szántai 11.09 13.98 Hungary 11.0913.6015.0417.0413.31

Megaminx

# Name Best Average Representing Solves
1 Bogdan Čumić 41.04 45.47 Serbia 49.8841.0443.6347.5245.25
2 Matej Bolta 47.69 49.82 Slovenia 56.1847.6950.3048.6850.49
3 Marcel Ručigaj 58.47 1:00.64 Slovenia 1:04.5658.4758.8259.281:03.81

Pyraminx

# Name Best Average Representing Solves
1 Đorđe Timotijević 3.21 4.25 Serbia 5.094.263.413.215.29
2 Luka Lukić 3.03 4.27 Serbia 4.943.153.034.725.25
3 Bálint Csengő 2.76 4.33 Hungary 6.853.296.042.763.67

Skewb

# Name Best Average Representing Solves
1 Bence Kiácz 2.47 3.54 Hungary 3.283.474.193.872.47
2 Szabolcs Szántai 3.10 4.17 Hungary 3.693.105.724.514.31
3 Bálint Csengő 2.87 5.42 Hungary 5.006.484.776.512.87

Square-1

# Name Best Average Representing Solves
1 Szabolcs Szántai 9.07 10.63 Hungary 11.789.829.0712.9410.29
2 Luka Jankovic 11.34 13.77 Serbia 11.3411.7913.2022.2916.33
3 Firmin Brault 10.12 14.04 France 10.1215.3013.1716.4913.64
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